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16x^2+9x^2=22^2
We move all terms to the left:
16x^2+9x^2-(22^2)=0
We add all the numbers together, and all the variables
25x^2-484=0
a = 25; b = 0; c = -484;
Δ = b2-4ac
Δ = 02-4·25·(-484)
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{48400}=220$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-220}{2*25}=\frac{-220}{50} =-4+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+220}{2*25}=\frac{220}{50} =4+2/5 $
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